python - Sort a file according to values in first column -

i have file containing results (integers) in several columns (tab separated), 2 lines of text @ beginning telling me file's contents , 2 lines @ end telling me if file's contents complete.

i have script order file according value of first column extend skips first two, , last 2 lines of file while printing out ordered first column. how so?

this script have:

file_name = "output1.dat"  new_file_name = "sorted_"+file_name data = csv.reader(open(file_name),delimiter='\t') sortedlist = sorted(data, key=lambda x:int(x[0])) #now write sorte result new csv file open(new_file_name, "wb") f:     filewriter = csv.writer(f, delimiter=',')     row in sortedlist:         filewriter.writerow(row) 

it gets tripped lines of text don't contain columns.

this should skip first 2 , last 2 lines:

sortedlist = sorted(list(data)[2:-2], key=lambda x:int(x[0])) 

write first column:

filewriter.writerow(row[:1]) 

full script:

file_name = "output1.dat"  new_file_name = "sorted_"+file_name data = csv.reader(open(file_name),delimiter='\t') sortedlist = sorted(list(data)[2:-2], key=lambda x:int(x[0])) #now write sorte result new csv file open(new_file_name, "wb") f:     filewriter = csv.writer(f, delimiter=',')     row in sortedlist:         filewriter.writerow(row[:1])