regex - GET img src from array query results PHP -

i need take img src record after query:

while ($row = mysqli_fetch_array($result, mysqli_assoc)) {   $rows[] = array(      'id' => $row['id_content'],      'titolo' => $row['titolo'],      'articolo' => $row['descrizione'],      'giorno' => $row['giorno'],      'foto' => "get img src this: $row['descrizione']",      'fonte' => $row['fonte'] );} 

is possible? try preg_match_all('/<img[^>]+>/i',$row['descrizione'],$res[0]) 1 result!

ok solve so:

create function:

function srcimg($num) {             preg_match('@src="([^"]+)"@',$num,$match);             $src = array_pop($match);             return $src;          } 

and then:

while ($row = mysqli_fetch_array($result, mysqli_assoc)) {   $rows[] = array(      'id' => $row['id_content'],      'titolo' => $row['titolo'],      'articolo' => $row['descrizione'],      'giorno' => $row['giorno'],      'foto' => srcimg($row['descrizione']),      'fonte' => $row['fonte'] );} echo json_encode($rows); 

i'd highly recommend @javier núñez suggest, , use html parser regex cannot cover eventualities this. if reason can't, try using regex: (untested)

src=['"]([^"]+)['"] 

and can use in preg_match follows:

preg_match( '@src=['"]([^"]+)['"]@', $row['descrizione'], $match); $src = array_pop($match); 

you can tinker if need hacky approach. understand urgency working on more perfect solution. ;)

you can use http://regexr.com/ test regex if want try , make more robust.

edit: didn't use preg_match_all. you'll want use instead.