c++ - How can I pass this pointer by reference? -

new pointers , reference i'm not sure on i'm trying pass pointers *mindatavalue , *maxdatavalue values changed when come functions. of in code, values don't change (as evident testing code), how set them , have change make them pass reference value can change when function done. thanks!

 void findminandmax(int array[], int size, int *min, int *max) {    int smallest = array[0];   int largest = array[0];    min = &smallest;   max = &largest;    (int = 1; < size; i++)   {     if (array[i] > largest){       largest = array[i];     }     if (array[i] < smallest){       smallest = array[i];     }   }    // testing code   cout << *min << endl;   cout << *max << endl;  }  int *makefrequency (int data[], int dsize, int *mindatavalue, int    *maxdatavalue) {     cout << *mindatavalue << endl;// testing code    cout << *maxdatavalue << endl;// testing code     findminandmax(data, dsize, mindatavalue, maxdatavalue); // how pass value changes after min , max found?      cout << *mindatavalue << endl; // testing code    cout << *maxdatavalue << endl;// testing code  }  int main() {  int dsize; int *arrayofints;    cout << "how many data values? ";   cin >> dsize;    arrayofints = new int [dsize];    getdata(dsize, arrayofints);    int *frequency, min, max;    frequency = makefrequency(arrayofints, dsize, &min, &max);  } 

you can either take function take pointer-to-pointer:

int *makefrequency (int data[], int dsize, int **mindatavalue, int **maxdatavalue) 

and modify

*mindatavalue , *maxdatavalue

inside function. in case, calling code must passa pointer pointer explicitly:

int *min, *max; makefrequency (data, size, &min, &max) 

the second possiblity pass reference pointer:

int *makefrequency (int data[], int dsize, int*& mindatavalue, int    *& maxdatavalue) 

in case modify pointer inside function , pass pointer function.

i'd prefer 1st way, because calling code looks different, fact pointers may modified inside function visible calling code too.