i trying fetch ip-address column present in both tables, a , b. table a has many ip-adresses , specific ip-address not present in table b. want distinct ip-addresses both tables. means want ip-adresses table a not present in table b, plus ip-adresses table b not present in table a. trying below code giving me ip-adresses not present in table b. please help.
var ips= (from in cs.a !cs.b.any(f => f.ipaddress == a.ipaddress) select a.ipaddress).distinct();
you can use
var ips= ((from in cs.a !cs.b.any(f => f.ipaddress == a.ipaddress) select a.ipaddress).distinct()).union((from b in cs.b !cs.a.any(f => f.ipaddress == b.ipaddress) select b.ipaddress).distinct());
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