c# - Counting occurrences of the first x elements of sublist in all sublists of the jagged list without grouping -

i'm having jagged list.

var jaggedlist = new list<list<string>>() { cc kk ww } { cc kk aa } { cc oo ll } { cc jj oo } { ww oo kk } { ww oo gg } { ww gg kk } { kk ll oo } { ll kk nn } { mm nn oo } { mm nn jj } 

i'm having linq command want grouping.

var dic = jaggedlist.groupby(lst => string.join(" ", lst.take(2)))                      .todictionary(el => el.key, el => el.count()); 

now want command edited not group.

i not sure want, please check it:

p.s. dic variable not dictionary, because if want same count jaggedlist, there key dublicates inadmissible dictionary collection.

    var n = 2;      var jaggedlist = new list<list<string>>(){             new list<string>{ "cc", "kk", "ww" },             new list<string>{ "cc", "kk", "aa" },             new list<string>{ "cc", "oo", "ll" },             new list<string>{ "cc", "jj", "oo" },             new list<string>{ "ww", "oo", "kk" },             new list<string>{ "ww", "oo", "gg" },             new list<string>{ "ww", "gg", "kk" },             new list<string>{ "kk", "ll", "oo" },             new list<string>{ "ll", "kk", "nn" },             new list<string>{ "mm", "nn", "oo" },             new list<string>{ "mm", "nn", "jj" }     };      func<ienumerable<string>, int, string> getkey = (col, num) => col.take(num).aggregate((a, b) => + " " + b);      var dic = jaggedlist.select(x => {         var key = getkey(x, n);         return new {              key,             count = jaggedlist.where(y => getkey(y, n) == key).count()         };     }).tolist();