i have xml (that external part) outputs:
...<prop name="day">monday</prop> <prop name="week">2</prop>...
i wondering if @ possible use xsl display image instead of name of day? name of day change 7 possible variables , need show different image each day of week.
so result i'm hoping this:
<img src="mondayimage.jpg"> <p>week number 2</p>
in xslt 2.0 van use index-of xpath function generate efficient lookup:
<xsl:transform xmlns:xsl="http://www.w3.org/1999/xsl/transform" version="2.0"> <xsl:output indent="yes"/> <xsl:param name="days" select="('monday', 'tuesday', 'wednesday', 'thursday', 'friday', 'saturday', 'sunday')"/> <xsl:param name="day-image" select="('image1.png','image2.png','image3.png','image4.png','image5.png','image6.png','image7.png')"/> <xsl:template match="/root"> <root> <xsl:apply-templates/> </root> </xsl:template> <xsl:template match="prop[@name='day']"> <img src="{$day-image[index-of($days, current())]}"/> </xsl:template> <xsl:template match="prop[@name='week']"> <p>week number <xsl:value-of select="."/></p> </xsl:template> </xsl:transform>
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